C Challenge

The Test has been designed by Director of Aspire Institute , Raithatha Yash .This Challenge checks ur fundamentals in C language . This test will be helpful to all the students who are preparing for their placement . In case of any query please fil

Filloni Shpërndaje

C Challenge

1. main() {
char s[ ]="man";
int i;
for(i=0;s[ i ];i++)
printf("\n %c", i[s] );
}//What is o/p?

Pyetje 1 out of 20

(A)man (B) nam (C)mmm (D)compilation error

C Challenge

2. main(){
static int var = 5;
if(--var)
main();
printf("%d ",var++);
}//What is o/p?

Pyetje 2 out of 20

A)0 1 2 3 4 B)1 2 3 4 5 C) compile error D)0 0 0 0 0

C Challenge

3. main() {
float c[]={1,2.2,3.2};
float i,p=c,q=c;
for( i =0; i<3;i++,q++;)
printf("%2.1f ",c);
for(i=0 ; i<3 ; i++,(p)++)
printf("%2.1f ",p);
}//What is o/p?

Pyetje 3 out of 20

A)1.0 2.2 3.2 1.0 2.2 3.2 B)1.0 1.0 1.0 1.0 2.2 3.2 C)1 2 3 1 2 3 D)1 1 1 1 2 3

C Challenge

4. main() {
printf("\rbba");
printf("\baab");
printf("\raa");
}//What is o/p?

Pyetje 4 out of 20

A) aa B)aaaab C)aabab D)bbaaa

C Challenge

5. main()
{
char str[] = "Hello World";
display(str);
}
void display(char *string)
{
printf("%s",string);
}//What is o/p?

Pyetje 5 out of 20

(A)Hello World (B) Hello (C)H (D)Compilation Error

C Challenge

6. main()
{
int a[3][2][2] = { {1,2,3,4}, {5,6,7,8},{9,10,11,12} };
int p,q;
p=&a[3][2][2];
*q=***a;
printf("%d-%d",p,q);
}//What is o/p?

Pyetje 6 out of 20

(A)12-1 (B)9-1 (C)1-12 (D)None of these

C Challenge

7. #define f(a,b) a/b
main() {
int x=5,y=6;
printf("\n%d",f(x6,yx));
}//What is o/p?

Pyetje 7 out of 20

(A)1 (B)25 (C)30 (D)None of these

C Challenge

8. main() {
char ch="Computer ";
while(ch!='\0') {
++ch;
printf("%c ",ch); ch ++; }
}//What is o/p?

Pyetje 8 out of 20

(C)Cpmquues (A)Dpnqvufs (B)Donpvtfr (D)None of these

C Challenge

9. main() { static char names[5][7]={"pascal","java","cobol","fortran","perl"}; int i; char *ch; ch=names[3]; names[3]=names[4]; names[4]=ch; printf("%s",names[4]); }

Pyetje 9 out of 20

(C)fortran (D)perl (A)Compilation Error : Array index out of Bound (B)Compilation Error: char Array is constant Pointer

C Challenge

10. enum colors {BLACK,BLUE,GREEN}
main() {
int i=1;
switch(i) {
case BLACK: printf("GOOD");
break;
case BLUE: printf("BAD");
break;
}
}

Pyetje 10 out of 20

(A)compilation Error (B) GOOD (C)BAD (D)runtime error

C Challenge

11. main( ) {
int x=10,y=10,p1,p2,k;
p1=&x;
p2=&y;
k=5 + p1 /p2;
printf(“%d”,k);
}

Pyetje 11 out of 20

A)6 B)5 c)Compile Error d)None of these

C Challenge

12. main( ) {
char *q;
int j;
for (j=0; j<3; j++)
scanf(“%s” ,(q+j));
printf(“%s” ,(q));
}//Input are:YASH ,PRIYAM,JAYESH

Pyetje 12 out of 20

(A)YPJAYESH (B)YASH (C)JAYESH (D)None of these

C Challenge

13. main ( ) {
static char ch[ ] = {"black", "white", "yellow", "violet"};
char ptr[ ] = {ch+3, ch+2, ch+1, ch}, p;
p = ptr;
**++p;
printf(" %s",(----p + 4));
}

Pyetje 13 out of 20

(A)ow (B)et (C)k (D)e

C Challenge

14. main() {
void f1();
void f2();
f1();
}
void f1() {
f2();
printf(“in f1”);
}
void f2() {
printf(“in f2”);
}//what is o/p?

Pyetje 14 out of 20

(A) Compilation Error (D)None of these (B)in f2 (C) in f2in f1 (C) in f2in f1

C Challenge

15. f2(a,b)
int a;
float b; {
return( a = !(a==b) );
}
main() {
int p1(), f2();
printf("The value is %d \n ",p1(f2,6,6.0));
}
p1(f2,val1,val2)
int (f2) ();
int val1;
float val2;
{
return((f2) (val1,val2));
}

Pyetje 15 out of 20

(A) The value is 0 (B) The value is 1 (C) The value is 0.0 (D)Compilation Error

C Challenge

16. main() {
char p; int q; long *r;
p=q=r=0;
p++; q++; r++;
printf("%p...%p...%p",p,q++,r++);
}

Pyetje 16 out of 20

A)0001...0004...0008 B)0001...0002...0004 C)0001...0002...0002 D)0002...0004...0008

C Challenge

17. void scan(int* size) {
*size=110;
}
main() {
int array_size;
scan(&array_size);
printf("%d",array_size);
}

Pyetje 17 out of 20

(C)compile Error (A)110 (B)address of “array size” (D)None of these

C Challenge

18. f(int n) {
If(n>0) return (n + f(n-1));
}
main() {
printf(“%d”,f(10));
}

Pyetje 18 out of 20

C Challenge

19. main() {
Char *ch = “hello”;
printf(ch);
}

Pyetje 19 out of 20

(C)run time error (A) hello (B) compilation error (D) None of these

C Challenge

20. void main(){
int x=1,y=0;
if (++x > 2)
if(++y<5)
y=100;
else
x=100;
printf(“ %d %d”, x,y);
}

Pyetje 20 out of 20

A)100 0 B)100 100 C)100 2 D)None of these

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C Challenge

The Test has been designed by Director of Aspire Institute , Raithatha Yash .This Challenge checks ur fundamentals in C language . This test will be helpful to all the students who are preparing for their placement . In case of any query please fil

1. main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n %c", i[s] ); }//What is o/p?

2. main(){ static int var = 5; if(--var) main(); printf("%d ",var++); }//What is o/p?

3. main() { float c[]={1,2.2,3.2}; float i,*p=c,*q=c; for( i =0; i<3;i++,*q++;) printf("%2.1f ",*c); for(i=0 ; i<3 ; i++,(*p)++) printf("%2.1f ",*p); }//What is o/p?

4. main() { printf("\rbba"); printf("\baab"); printf("\raa"); }//What is o/p?

5. main() { char str[] = "Hello World"; display(str); } void display(char *string) { printf("%s",string); }//What is o/p?

6. main() { int a[3][2][2] = { {1,2,3,4}, {5,6,7,8},{9,10,11,12} }; int *p,*q; p=&a[3][2][2]; *q=***a; printf("%d-%d",*p,*q); }//What is o/p?

7. #define f(a,b) a/b main() { int x=5,y=6; printf("\n%d",f(x*6,y*x)); }//What is o/p?

8. main() { char *ch="Computer "; while(*ch!='\0') { ++*ch; printf("%c ",*ch); ch ++; } }//What is o/p?

9. main() { static char names[5][7]={"pascal","java","cobol","fortran","perl"}; int i; char *ch; ch=names[3]; names[3]=names[4]; names[4]=ch; printf("%s",names[4]); }

10. enum colors {BLACK,BLUE,GREEN} main() { int i=1; switch(i) { case BLACK: printf("GOOD"); break; case BLUE: printf("BAD"); break; } }

11. main( ) { int x=10,y=10,*p1,*p2,k; p1=&x; p2=&y; k=5 + *p1 /*p2; printf(“%d”,k); }

12. main( ) { char *q; int j; for (j=0; j<3; j++) scanf(“%s” ,(q+j)); printf(“%s” ,(q)); }//Input are:YASH ,PRIYAM,JAYESH

13. main ( ) { static char *ch[ ] = {"black", "white", "yellow", "violet"}; char **ptr[ ] = {ch+3, ch+2, ch+1, ch}, ***p; p = ptr; **++p; printf(" %s",(*--*--p + 4)); }

14. main() { void f1(); void f2(); f1(); } void f1() { f2(); printf(“in f1”); } void f2() { printf(“in f2”); }//what is o/p?

15. f2(a,b) int a; float b; { return( a = !(a==b) ); } main() { int p1(), f2(); printf("The value is %d \n ",p1(f2,6,6.0)); } p1(f2,val1,val2) int (*f2) (); int val1; float val2; { return((*f2) (val1,val2)); }

16. main() { char *p; int *q; long *r; p=q=r=0; p++; q++; r++; printf("%p...%p...%p",p,q++,r++); }

17. void scan(int* size) { *size=110; } main() { int array_size; scan(&array_size); printf("%d",array_size); }

18. f(int n) { If(n>0) return (n + f(n-1)); } main() { printf(“%d”,f(10)); }

19. main() { Char *ch = “hello”; printf(ch); }

20. void main(){ int x=1,y=0; if (++x > 2) if(++y<5) y=100; else x=100; printf(“ %d %d”, x,y); }

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Aplikacionet e sugjeruara

1. main() {
char s[ ]="man";
int i;
for(i=0;s[ i ];i++)
printf("\n %c", i[s] );
}//What is o/p?

2. main(){
static int var = 5;
if(--var)
main();
printf("%d ",var++);
}//What is o/p?

3. main() {
float c[]={1,2.2,3.2};
float i,p=c,q=c;
for( i =0; i<3;i++,q++;)
printf("%2.1f ",c);
for(i=0 ; i<3 ; i++,(p)++)
printf("%2.1f ",p);
}//What is o/p?

4. main() {
printf("\rbba");
printf("\baab");
printf("\raa");
}//What is o/p?

5. main()
{
char str[] = "Hello World";
display(str);
}
void display(char *string)
{
printf("%s",string);
}//What is o/p?

6. main()
{
int a[3][2][2] = { {1,2,3,4}, {5,6,7,8},{9,10,11,12} };
int p,q;
p=&a[3][2][2];
*q=***a;
printf("%d-%d",p,q);
}//What is o/p?

7. #define f(a,b) a/b
main() {
int x=5,y=6;
printf("\n%d",f(x6,yx));
}//What is o/p?

8. main() {
char ch="Computer ";
while(ch!='\0') {
++ch;
printf("%c ",ch); ch ++; }
}//What is o/p?

10. enum colors {BLACK,BLUE,GREEN}
main() {
int i=1;
switch(i) {
case BLACK: printf("GOOD");
break;
case BLUE: printf("BAD");
break;
}
}

11. main( ) {
int x=10,y=10,p1,p2,k;
p1=&x;
p2=&y;
k=5 + p1 /p2;
printf(“%d”,k);
}

12. main( ) {
char *q;
int j;
for (j=0; j<3; j++)
scanf(“%s” ,(q+j));
printf(“%s” ,(q));
}//Input are:YASH ,PRIYAM,JAYESH

13. main ( ) {
static char ch[ ] = {"black", "white", "yellow", "violet"};
char ptr[ ] = {ch+3, ch+2, ch+1, ch}, p;
p = ptr;
**++p;
printf(" %s",(----p + 4));
}

14. main() {
void f1();
void f2();
f1();
}
void f1() {
f2();
printf(“in f1”);
}
void f2() {
printf(“in f2”);
}//what is o/p?

15. f2(a,b)
int a;
float b; {
return( a = !(a==b) );
}
main() {
int p1(), f2();
printf("The value is %d \n ",p1(f2,6,6.0));
}
p1(f2,val1,val2)
int (f2) ();
int val1;
float val2;
{
return((f2) (val1,val2));
}

16. main() {
char p; int q; long *r;
p=q=r=0;
p++; q++; r++;
printf("%p...%p...%p",p,q++,r++);
}

17. void scan(int* size) {
*size=110;
}
main() {
int array_size;
scan(&array_size);
printf("%d",array_size);
}

18. f(int n) {
If(n>0) return (n + f(n-1));
}
main() {
printf(“%d”,f(10));
}

19. main() {
Char *ch = “hello”;
printf(ch);
}

20. void main(){
int x=1,y=0;
if (++x > 2)
if(++y<5)
y=100;
else
x=100;
printf(“ %d %d”, x,y);
}